ÌâÄ¿ÄÚÈÝ

4£®ÏÂÃæÊÇСÃñͬѧÓÃÌìÆ½ºÍÁ¿Í²×ö¡°²â¶¨ÑÎË®µÄÃܶȡ±ÊµÑéµÄÊý¾Ý¼Ç¼±í£®
£¨1£©Çë¸ù¾Ý¼Ç¼Êý¾ÝÌîºÃ±í¸ñµÄ¿Õ¸ñ£®
ÈÝÆ÷µÄÖÊÁ¿
£¨g£©
ÈÝÆ÷ºÍÑÎË®µÄ×ÜÖÊÁ¿£¨g£©ÑÎË®µÄÌå»ý£¨cm3£©ÑÎË®µÄÃܶȣ¨kg/m3£©
10.564.5501.08
£¨2£©ÊµÑéÖеIJÙ×÷²½ÖèÓУº
A£®°ÑÑÎË®µ¹½øÁ¿Í²£¬ÓÃÁ¿Í²²â³öÑÎË®µÄÌå»ý£»            B£®ÓÃÌìÆ½²â³öÈÝÆ÷µÄÖÊÁ¿£»
C£®°ÑÑÎË®µ¹½øÈÝÆ÷£¬ÓÃÌìÆ½²â³öÈÝÆ÷ºÍÑÎË®µÄ×ÜÖÊÁ¿£»    D£®¼ÆËã³öÑÎË®µÄÃܶȣ®
¼ÆËã³öµÄÑÎË®µÄÃܶȻáÓëʵ¼ÊÑÎË®µÄÃܶÈÓÐÎó²î£®Èç¹ûʵÑéÖеIJÙ×÷²½ÖèÊǰ´ÉÏÊöµÄA£®B£®C£®D˳Ðò£¬Ôò²â³öµÄÑÎË®µÄÃܶȻáСÓÚʵ¼ÊÑÎË®µÄÃܶȣ¨Ñ¡ÌСÓÚ¡±¡¢¡°µÈÓÚ¡±¡¢¡°´óÓÚ¡±£©£»Òª¼õÉÙʵÑéÎó²î£¬¸üºÃµÄʵÑé²Ù×÷˳ÐòÓ¦ÊÇCABD£®

·ÖÎö ²âÒºÌåµÄÃܶȵÄÔ­ÀíÊǦÑ=$\frac{m}{V}$£¬¾ßÌå×öʱҪ¿¼ÂÇÒºÌå´ÓÈÝÆ÷È«µ¹³öʱÈÝÆ÷±ÚÕ³ÉÙÁ¿ÒºÌåµÄÇé¿ö£¬´Ó¶øÓ°ÏìʵÑé½á¹û£®

½â´ð ½â£º£¨1£©ÑÎË®ÖÊÁ¿m=64.5g-10.5g=54.0g£¬ÑÎË®ÃܶȦÑ=$\frac{m}{V}$=$\frac{54.0g}{50c{m}^{3}}$=1.08g/cm3=1.08¡Á103kg/m3
£¨2£©°´ÌâÖÐabcd˳Ðò×ö£¬ÑÎË®²»ÄÜ´ÓÁ¿Í²È«²¿µ¹ÈëÉÕ±­£¬ÖÂʹËù²âÑÎË®ÖÊÁ¿Æ«Ð¡£¬ÃÜ¶ÈÆ«Ð¡£®
Ϊ·ÀÖ¹ÈÝÆ÷±ÚÕ³ÒºÌåÓ°ÏìËù²â½á¹û£¬ÒªÏȲâÉÕ±­¡¢ÑÎË®×ÜÖÊÁ¿£¬ÔÙ½«ÑÎË®µ¹ÈëÁ¿Í²²âÌå»ý£¬²¢²âµ¹×ßÑÎË®ºóÉÕ±­µÄÖÊÁ¿£®
¹Ê´ð°¸Îª£º£¨1£©1.08£»£¨2£©Ð¡ÓÚ£»CABD£®

µãÆÀ ´ËÌâÊDzâÁ¿ÑÎË®µÄÃܶÈʵÑ飬¿¼²éÁËÃܶȵļÆËã¼°¶ÔʵÑéÎó²îµÄ·ÖÎö¼°¼õСÎó²îµÄ·½·¨£¬ÔÚ²âÁ¿ÒºÌåÃܶÈʱ£¬Òª¼õСʵÑéÎó²î£¬Ðè×¢ÒâÁ¿Í²ÖÐÒºÌåµÄÖÊÁ¿ºÍÌå»ýµÄͳһ£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø