如图,△ABC是边长为2的等边三角形,将△ABC沿射线BC向右平移得到△DCE,连接AD、BD,下列结论错误的是( )

A.AD∥BC
B.AC⊥BD
C.四边形ABCD面积为4
D.四边形ABED是等腰梯形
0 157862 157870 157876 157880 157886 157888 157892 157898 157900 157906 157912 157916 157918 157922 157928 157930 157936 157940 157942 157946 157948 157952 157954 157956 157957 157958 157960 157961 157962 157964 157966 157970 157972 157976 157978 157982 157988 157990 157996 158000 158002 158006 158012 158018 158020 158026 158030 158032 158038 158042 158048 158056 366461
A.AD∥BC
B.AC⊥BD
C.四边形ABCD面积为4
D.四边形ABED是等腰梯形