题目内容
因式分-x2+2xy+y2=______.
∵-x2+2xy+y2
=-(x2-2xy-y2)
=-(x2-y2-2xy)
=-[(x-y)2-(
y)2]
=-(x-y+
y)(x-y-
y).
故答案为:-(x-y+
y)(x-y-
y).
=-(x2-2xy-y2)
=-(x2-y2-2xy)
=-[(x-y)2-(
| 2 |
=-(x-y+
| 2 |
| 2 |
故答案为:-(x-y+
| 2 |
| 2 |
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