题目内容
因式分
①x2-4x+3
②x2y+5xy-36y
③9-x2+2xy-y2.
①x2-4x+3
②x2y+5xy-36y
③9-x2+2xy-y2.
①x2-4x+3=(x-1)(x-3);
②x2y+5xy-36y=y(x2+5x-36)=y(x-4)(x+9);
③9-x2+2xy-y2=9-(x2-2xy+y2)=9-(x-y)2=(3-x+y)(3+x-y).
②x2y+5xy-36y=y(x2+5x-36)=y(x-4)(x+9);
③9-x2+2xy-y2=9-(x2-2xy+y2)=9-(x-y)2=(3-x+y)(3+x-y).
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