题目内容
下列变形是怎样得到的?
(1)由x>y,得
x-3>
y-3;
(2)由x>y,得
(x-3)>
(y-3);
(3)由x>y,得2(3-x)<2(3-y).
(1)由x>y,得
| 1 |
| 2 |
| 1 |
| 2 |
(2)由x>y,得
| 1 |
| 2 |
| 1 |
| 2 |
(3)由x>y,得2(3-x)<2(3-y).
(1)x>y,
两边除以2得:
x>
y,
两边减去3得:
x-3>
y-3;
(2)x>y,
两边减去3得:x-3>y-3,
两边除以2得:
(x-3)>
(y-3);
(3)x>y,
两边除以-1得:-x<-y,
两边加上3得:3-x<3-y,
两边乘以2得:2(3-x)<2(3-y).
两边除以2得:
| 1 |
| 2 |
| 1 |
| 2 |
两边减去3得:
| 1 |
| 2 |
| 1 |
| 2 |
(2)x>y,
两边减去3得:x-3>y-3,
两边除以2得:
| 1 |
| 2 |
| 1 |
| 2 |
(3)x>y,
两边除以-1得:-x<-y,
两边加上3得:3-x<3-y,
两边乘以2得:2(3-x)<2(3-y).
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