题目内容
计算
(1)12+(-8)+11+(-2)+(-12);
(2)
÷(
+
-
);
(3)(-1)3×(-5)÷[-32+(-2)2].
(1)12+(-8)+11+(-2)+(-12);
(2)
| 1 |
| 18 |
| 2 |
| 3 |
| 1 |
| 6 |
| 1 |
| 2 |
(3)(-1)3×(-5)÷[-32+(-2)2].
(1)原式=12-8+11-2-12
=4+11-2-12
=15-2-12
=13-12
=1;
(2)原式=
÷
=
×3
=
;
(3)原式=(-1)3×(-5)÷[-9+4]
=(-1)×(-5)×(-
)
=5×(-
)
=-1.
=4+11-2-12
=15-2-12
=13-12
=1;
(2)原式=
| 1 |
| 18 |
| 1 |
| 3 |
=
| 1 |
| 18 |
=
| 1 |
| 6 |
(3)原式=(-1)3×(-5)÷[-9+4]
=(-1)×(-5)×(-
| 1 |
| 5 |
=5×(-
| 1 |
| 5 |
=-1.
练习册系列答案
相关题目