题目内容
(1)计算:2cos45°+|
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(2)先化简,再求值:2sin230°•tan30°+cos60°•tan60.
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(2)先化简,再求值:2sin230°•tan30°+cos60°•tan60.
(1)原式=2×
+
-
=
+
-
=
;
(2)原式=2sin230°•tan30°+sin30°•tan60°
=sin30°(2sin30°•tan30°+tan60°)
=
(2×
×
+
)
=
(
+
)
=
.
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=
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=
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(2)原式=2sin230°•tan30°+sin30°•tan60°
=sin30°(2sin30°•tan30°+tan60°)
=
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=
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=
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