题目内容
先化简,再求值:
÷(2x-
),其中x=
+1.
| x2+2x+1 |
| x2+x |
| 1+x2 |
| x |
| 2 |
(本题满分5分)
原式=
÷
(1分)
=
•
.(2分)
=
.(1分)
当x=
+1时,原式=
=
=
.(1分)
原式=
| x2+2x+1 |
| x2+x |
| x2-1 |
| x |
=
| (x+1)2 |
| x(x+1) |
| x |
| (x+1)(x-1) |
=
| 1 |
| x-1 |
当x=
| 2 |
| 1 | ||
|
| 1 | ||
|
| ||
| 2 |
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