题目内容
先化简再求值:5xy2-[2x2y-(2x2y-xy2)]-4xy2-x,其中,x=-
,y=16
.
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5xy2-[2x2y-(2x2y-xy2)]-4xy2-x
=5xy2-[2x2y-2x2y+xy2]-4xy2-x
=5xy2-xy2-4xy2-x
=-x
当x=-
,y=16
时,原式=-(-
)=
.
=5xy2-[2x2y-2x2y+xy2]-4xy2-x
=5xy2-xy2-4xy2-x
=-x
当x=-
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