题目内容
x2-3x+________=(x-________)2;
配方x2+3x+_________=( )2.
用换元法解方程x2-3x+=4时,设y=x2-3x,则原方程可化为
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在空白处填上适当的数,将多项或配成完全平方式:
(1)x2-3x+(________)=(x-________)2;
(2)x2+x+(________)=(x+________)2;
(3)9x2-12x+(________)=9(x-________)2=(3x-________)2.
用适当的数填空:x2-3x+________=(x-________)2.