题目内容
(1)计算:
+(
+π)0-|1-
|;
(2)分解因式:a3-ab2.
| 3 | 27 |
| 5 |
| 2 |
(2)分解因式:a3-ab2.
(1)
+(
+π)0-|1-
|
=3+1-
+1
=5-
;
(2)a3-ab2
=a(a2-b2)
=a(a+b)(a-b).
| 3 | 27 |
| 5 |
| 2 |
=3+1-
| 2 |
=5-
| 2 |
(2)a3-ab2
=a(a2-b2)
=a(a+b)(a-b).
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