题目内容
先将(| x2-x |
| x2-1 |
| 1 |
| x+1 |
| 2x |
| x-1 |
分析:先化简二次根式,再选择一个数代入求值即可.
解答:解:原式=[
-
]•
,(2分)
=
•
,
=
,(4分)
取x=-3,则原式=
=3(6分).
| x(x-1) |
| (x-1)(x+1) |
| 1 |
| x+1 |
| 2x |
| x-1 |
=
| x-1 |
| x+1 |
| 2x |
| x-1 |
=
| 2x |
| x+1 |
取x=-3,则原式=
| 2x |
| x+1 |
点评:本题考查了分式的化简求值,解此题的关键是化简分式.
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