题目内容

化简:
(1)
12
m2-9
-
2
m-3
            
(2)(
x2-4
x2-4x+4
-
x-2
x+2
)÷
x
x-2
考点:分式的混合运算
专题:
分析:(1)把分式进行通分,然后相减即可;
(2)首先把括号内的式子化简,把除法转化为乘法,然后利用利用分配律计算乘法,最后通分相减即可.
解答:解:(1)原式=
12
(m+3)(m-3)
-
2(m+3)
(m+3)(m-3)

=
12-2(m+3)
(m+3)(m-3)

=
6-2m
(m+3)(m-3)

=-
2
m+3

(2)原式=【
(x+2)(x-2)
(x-2)2
-
x-2
x+2
】•
x-2
x

=(
x+2
x-2
-
x-2
x+2
)•
x-2
x

=
x+2
x
-
(x-2)2
(x+2)x

=
(x+2)2-(x-2)2
x(x+2)

=
8x
x(x+2)

=
8
x+2
点评:本题主要考查分式的混合运算,通分、因式分解和约分是解答的关键.
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