题目内容
计算:
(1)(-2012)0+(-3)2-(
)-1
(2)(x-2y)2-(x+2y)(x-2y)
(1)(-2012)0+(-3)2-(
| 1 |
| 4 |
(2)(x-2y)2-(x+2y)(x-2y)
(1)原式=1+9-4=6;
(2)原式=x2-4xy+4y2-(x2-4y2)=x2-4xy+4y2-x2+4y2=-4xy+8y2.
(2)原式=x2-4xy+4y2-(x2-4y2)=x2-4xy+4y2-x2+4y2=-4xy+8y2.
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