题目内容
如图,AB为⊙O的直径,点C在⊙O上,若∠C=15°,则∠BOC =( ).
A.60° B.45° C.30° D.15°
C
如图,AB为⊙O的直甲径,PD切⊙O于点C,交AB的延长线于D,且CO=CD,则∠PCA=
A.60°
B.65°
C.67.5°
D.75°