题目内容
(1)计算:cos260°+sin245°-tan60°
(2)|-3|+(-1)2011×(π-3)0-
+(
)-1.
(2)|-3|+(-1)2011×(π-3)0-
| 3 | 27 |
| 1 |
| 2 |
(1)原式=(
)2+(
)2-
=
+
-
=
;
(2)原式=3+(-1)×1-3+2=3-1-3+2=1.
| 1 |
| 2 |
| ||
| 2 |
| 3 |
| 1 |
| 4 |
| 1 |
| 2 |
| 3 |
3-4
| ||
| 4 |
(2)原式=3+(-1)×1-3+2=3-1-3+2=1.
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