题目内容
计算与化简
(1)
×(-4)2-0.25×(-5)÷(-
)3;
(2)当x=-
,y=-3时,求代数式3(x2-2xy)-[3x2-2y+2(xy+y)]的值.
(1)
| 5 |
| 8 |
| 1 |
| 2 |
(2)当x=-
| 1 |
| 2 |
(1)
×(-4)2-0.25×(-5)÷(-
)3
=
×16-0.25×(-5)÷(-
)
=10-0.25×5×8
=10-10
=0;
(2)3(x2-2xy)-[3x2-2y+2(xy+y)]
=3x2-6xy-[3x2-2y+2xy+2y]
=3x2-6xy-3x2-2xy
=-8xy;
当x=-
,y=-3时,
-8xy=-8×(-
)×(-3)=-12.
| 5 |
| 8 |
| 1 |
| 2 |
=
| 5 |
| 8 |
| 1 |
| 8 |
=10-0.25×5×8
=10-10
=0;
(2)3(x2-2xy)-[3x2-2y+2(xy+y)]
=3x2-6xy-[3x2-2y+2xy+2y]
=3x2-6xy-3x2-2xy
=-8xy;
当x=-
| 1 |
| 2 |
-8xy=-8×(-
| 1 |
| 2 |
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