题目内容
计算(先化简,再求值):(
-
)÷
,其中a=
+1.
| 3a-1 |
| a2-1 |
| 2 |
| a+1 |
| 1 |
| a2-2a+1 |
| 2 |
原式=
×(a-1)2
=
×(a-1)2
=a-1,
当a=
+1时,原式=
+1-1=
.
| (3a-1)-2(a-1) |
| (a+1)(a-1) |
=
| 1 |
| a-1 |
=a-1,
当a=
| 2 |
| 2 |
| 2 |
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