题目内容
化简：
（1）(
)2÷(
)2•
（2）(
-
)÷
．
（1）(
| -a |
| b |
| 2a2 |
| 5b |
| a |
| 5b |
（2）(
| x+2 |
| x2-2x |
| x-1 |
| x2-4x+4 |
| x-4 |
| x |
（1）原式=
•
•
=
；
（2）原式=[
-
]•
=[
-
]•
=
•
=
．
| a2 |
| b2 |
| 25b2 |
| 4a4 |
| a |
| 5b |
=
| 5 |
| 4ab |
（2）原式=[
| x+2 |
| x(x-2) |
| x-1 |
| (x-2)2 |
| x |
| x-4 |
=[
| (x+2)(x-2) |
| x(x-2)2 |
| x(x-1) |
| x(x-2)2 |
| x |
| x-4 |
=
| x-4 |
| x(x-2)2 |
| x |
| x-4 |
=
| 1 |
| x2-4x+4 |
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