题目内容

若x-y=1,x3-y3=2,则x4+y4=______,x5-y5______.
∵x3-y3=(x-y)(x2+xy+y2)=2,
x-y=1,
x3-y3=(x-y)(x2+xy+y2)=2,
又∵x2-2xy+y2=1,与上式联立得:
xy=
1
3
,x2+y2=
5
3

故x4+y4=(x2+y22-2x2y2=
23
9


又x5-y5=x5-x4y+x4y-xy4+xy4-y5=x4(x-y)+xy(x3-y3)+y4(x-y),
将x-y=1,xy=
1
3
,x3-y3=2代入,
可得x5-y5=
29
9

故答案为
23
9
29
9
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