题目内容
计算:
(1)(-3xy2)3•(
x3y)2;
(2)4a2x2•(-
a4x3y3)÷(-
a5xy2);
(3)(2x-y)(4x2-y2)(2x+y);
(4)x2-(x+2)(x-2)-(x+
)2.
(1)(-3xy2)3•(
| 1 |
| 6 |
(2)4a2x2•(-
| 2 |
| 5 |
| 1 |
| 2 |
(3)(2x-y)(4x2-y2)(2x+y);
(4)x2-(x+2)(x-2)-(x+
| 1 |
| x |
(1)(-3xy2)3•(
x3y)2,
=-27x3y6•
x6y2,
=-
x9y8;
(2)4a2x2•(-
a4x3y3)÷(-
a5xy2),
=4a2x2•(-
)a4x3y3÷(-
)a5xy2,
=
ax4y;
(3)(2x-y)(4x2-y2)(2x+y),
=(4x2-y2)(4x2-y2),
=(4x2-y)2,
=16x4-8x2y2+y4;
(4)x2-(x+2)(x-2)-(x+
)2,
=x2-x2+4-x2-2-
,
=-x2+2-
.
| 1 |
| 6 |
=-27x3y6•
| 1 |
| 36 |
=-
| 3 |
| 4 |
(2)4a2x2•(-
| 2 |
| 5 |
| 1 |
| 2 |
=4a2x2•(-
| 2 |
| 5 |
| 1 |
| 2 |
=
| 16 |
| 5 |
(3)(2x-y)(4x2-y2)(2x+y),
=(4x2-y2)(4x2-y2),
=(4x2-y)2,
=16x4-8x2y2+y4;
(4)x2-(x+2)(x-2)-(x+
| 1 |
| x |
=x2-x2+4-x2-2-
| 1 |
| x2 |
=-x2+2-
| 1 |
| x2 |
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