题目内容
计算:-
-
-
-
-…-
= .
| 1 |
| 1×3 |
| 1 |
| 2×4 |
| 1 |
| 3×5 |
| 1 |
| 4×6 |
| 1 |
| 2015×2017 |
考点:有理数的混合运算
专题:计算题
分析:原式提取-1,拆项变形后,抵消合并即可得到结果.
解答:解:原式=-(
+
+
+
+…+
)
=-
×(1-
+
-
+…+
-
+
-
+
+…+
-
)
=-
×(1-
+
-
)
=-
×(
-
)
=-
.
故答案为:-
.
| 1 |
| 1×3 |
| 1 |
| 2×4 |
| 1 |
| 3×5 |
| 1 |
| 4×6 |
| 1 |
| 2015×2017 |
=-
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 5 |
| 1 |
| 2015 |
| 1 |
| 2017 |
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 4 |
| 1 |
| 2014 |
| 1 |
| 2016 |
=-
| 1 |
| 2 |
| 1 |
| 2017 |
| 1 |
| 2 |
| 1 |
| 2016 |
=-
| 1 |
| 2 |
| 3 |
| 2 |
| 4043 |
| 2016×2017 |
=-
| 3045661 |
| 4066272 |
故答案为:-
| 3045661 |
| 4066272 |
点评:此题考查了有理数的混合运算,熟练掌握运算法则是解本题的关键.
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