题目内容
如果x+
=2,则
=______.
| 1 |
| x |
| x2 |
| x4+x2+1 |
∵(x+
)2=x2+2+
=4,
∴x2+
=2,
∴
=
=
.
故本题答案为:
.
| 1 |
| x |
| 1 |
| x2 |
∴x2+
| 1 |
| x2 |
∴
| x2 |
| x4+x2+1 |
| 1 | ||
x2+1+
|
| 1 |
| 3 |
故本题答案为:
| 1 |
| 3 |
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方程
+
=1如果有增根,则此增根只可能是( )
| 1 |
| x+1 |
| 1 |
| x-a |
| A、0 | B、-1 | C、a或-1 | D、a |