题目内容
已知:A=2x2-x+1,A-2B=x-1,求B+A.
∵A-2B=x-1,A=2x2-x+1,
∴2B=A-(x-1)=2x2-x+1-(x-1)=2x2-x+1-x+1
=2x2-2x+2.
即:B=x2-x+1.
∴A+B=(2x2-x+1)+(x2-x+1)
=3x2-2x+2.
∴2B=A-(x-1)=2x2-x+1-(x-1)=2x2-x+1-x+1
=2x2-2x+2.
即:B=x2-x+1.
∴A+B=(2x2-x+1)+(x2-x+1)
=3x2-2x+2.
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