题目内容
计算或化简:
(1)4x-(x-3y)
(2)5a2-[3a-(2a-3)+4a2]
(3)(-
+
-
)÷(-
)
(4)(-3)3×[(-
)2-(-
)]-(-2)2÷4.
(1)4x-(x-3y)
(2)5a2-[3a-(2a-3)+4a2]
(3)(-
| 3 |
| 4 |
| 7 |
| 12 |
| 5 |
| 9 |
| 1 |
| 36 |
(4)(-3)3×[(-
| 1 |
| 3 |
| 10 |
| 9 |
考点:整式的加减,有理数的混合运算
专题:
分析:(1)先去括号,然后合并同类项求解;
(2)先去括号,然后合并同类项求解;
(3)根据有理数的运算法则求解;
(4)根据有理数的运算法则求解.
(2)先去括号,然后合并同类项求解;
(3)根据有理数的运算法则求解;
(4)根据有理数的运算法则求解.
解答:解:(1)原式=4x-x+3y
=3x+3y;
(2)原式=5a2-3a+2a-3+4a2
=a2-a-3;
(3)原式=27-21+20
=26;
(4)原式=-27×(
+
)-1
=33-1
=32.
=3x+3y;
(2)原式=5a2-3a+2a-3+4a2
=a2-a-3;
(3)原式=27-21+20
=26;
(4)原式=-27×(
| 1 |
| 9 |
| 10 |
| 9 |
=33-1
=32.
点评:本题考查了整式的加减,解答本题的关键是掌握去括号法则和合并同类项法则.
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