题目内容
计算下列各题:
(1)
(cos45°-sin60°)+
;
(2)(-2)0-3tan30°+|
-2|.
(1)
| 2 |
| ||
| 4 |
(2)(-2)0-3tan30°+|
| 3 |
分析:(1)把各特殊角的三角函数值代入进行计算即可;
(2)先把tan30°=
代入,再去绝对值符号,按照实数混合运算的顺序进行计算即可.
(2)先把tan30°=
| ||
| 3 |
解答:解:(1)原式=
(
-
)+
=
×
+
=
+
=1;
(2)原式=1-3×
+2-
=-1-
+2-
=1.
| 2 |
| ||
| 2 |
| ||
| 2 |
| ||
| 2 |
=
| 2 |
| ||||
| 2 |
| ||
| 2 |
=
2-
| ||
| 2 |
| ||
| 2 |
=1;
(2)原式=1-3×
| ||
| 3 |
| 3 |
=-1-
| 3 |
| 3 |
=1.
点评:本题考查的是实数的运算,熟知实数混合运算的法则是解答此题的关键.
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