题目内容
| 1 |
| 2002 |
| 1 |
| 3003 |
| 1 |
| 4004 |
| 1 |
| 6006 |
| 1 |
| 8008 |
分析:先把原式分解为两个分数的乘积的形式,再提取公因数,即可求出答案.
解答:解:
+
-
+
-
=
×
+
×
-
×
+
×
-
×
=
×(
+
-
+
-
)
=
×
=
.
故选C.
| 1 |
| 2002 |
| 1 |
| 3003 |
| 1 |
| 4004 |
| 1 |
| 6006 |
| 1 |
| 8008 |
=
| 1 |
| 1001 |
| 1 |
| 2 |
| 1 |
| 1001 |
| 1 |
| 3 |
| 1 |
| 1001 |
| 1 |
| 4 |
| 1 |
| 1001 |
| 1 |
| 6 |
| 1 |
| 1001 |
| 1 |
| 8 |
=
| 1 |
| 1001 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 6 |
| 1 |
| 8 |
=
| 1 |
| 1001 |
| 5 |
| 8 |
=
| 5 |
| 8008 |
故选C.
点评:此题考查了有理数的混合运算,用到的知识点是有理数的混合运算法则,解题的关键是把原式分解为两个分数的乘积的形式.
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