题目内容
计算题
(1)
÷(a2-4)•
;
(2)
÷(x+1)•
(1)
| a2-4 |
| a2+2a-8 |
| a2-4a+4 |
| a-2 |
(2)
| x2-1 |
| x2-4x+4 |
| x2-3x+2 |
| x-1 |
(1)原式=
•
•
=
;
(2)原式=
×
×
=
.
| (a+2)(a-2) |
| (a+4)(a-2) |
| 1 |
| (a+2)(a-2) |
| (a-2)2 |
| a-2 |
| 1 |
| a+4 |
(2)原式=
| (x+1)(x-1) |
| (x-2)2 |
| 1 |
| x+1 |
| (x-1)(x-2) |
| x-1 |
| x-1 |
| x-2 |
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