题目内容
计算:
(1)5
-2
+3
-
(2)
+
(3)(
-1)2(
+1)2
(4)-4×3
÷(6
)
.
(1)5
| 2 |
| 2 |
| 2 |
| 1 |
| 3 |
| 2 |
(2)
| 4 |
| ||
| 3 | -
| ||
(3)(
| 2 |
| 2 |
(4)-4×3
| 1 |
| 3 |
| 4 |
| 3 |
| 3 |
| 2 |
(1)原式=(5-2+3-
)
=
;
(2)
=
;
(3)原式=[(
-1) (
+1)2]
=(2-1)2
=1;
(4)原式=-4×
÷62
=-
.
| 1 |
| 3 |
| 2 |
=
| 17 |
| 5 |
| 2 |
(2)
| 4 | (
| ||
| 4 |
| 3 |
(3)原式=[(
| 2 |
| 2 |
=(2-1)2
=1;
(4)原式=-4×
| 3 | 3 |
=-
| |||
| 9 |
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