题目内容
先化简,再求值:3x2y-[2xy2-2(xy-
x2y)+xy]+3xy2,其中,x=
,y=-
.
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原式=3x2y-2xy2+2(xy-
x2y)-xy+3xy2=3x2y-2xy2+2xy-3x2y-xy+3xy2=xy2+xy,
当x=
,y=-
时,原式=-
.
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当x=
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