题目内容
先将| x2+2x |
| x-1 |
| 1 |
| x |
分析:首先括号式子进行通分,然后把分式分子分母能分解因式的分解因式,然后约分化简,最后再代入求值.
解答:解:
•(1-
)
=
•
=
•
=x+2,
当x=2时,x+2=4.
故答案为4.
| x2+2x |
| x-1 |
| 1 |
| x |
=
| x2+2x |
| x-1 |
| x-1 |
| x |
=
| x(x+2) |
| x-1 |
| x-1 |
| x |
=x+2,
当x=2时,x+2=4.
故答案为4.
点评:本题的关键是化简,通分和约分是解题的关键,注意最后代值时一定注意分母不为0.
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