题目内容
先化简,再求值:
-
÷(x+1-
),其中x满足x2+2x-4=0.
| 1 |
| x+2 |
| x2-4x+4 |
| x2-x |
| 3 |
| x-1 |
分析:把括号里通分,将除法转化为乘法,分子、分母因式分解,约分,最后通分,整体代入求值.
解答:解:原式=
-
÷
=
-
•
=
-
=
,
由x2+2x-4=0,得x2+2x=4,
原式=
=
.
| 1 |
| x+2 |
| (x-2)2 |
| x(x-1) |
| (x+1)(x-1)-3 |
| x-1 |
=
| 1 |
| x+2 |
| (x-2)2 |
| x(x-1) |
| x-1 |
| (x+2)(x-2) |
=
| 1 |
| x+2 |
| x-2 |
| x(x+2) |
=
| 2 |
| x2+2x |
由x2+2x-4=0,得x2+2x=4,
原式=
| 2 |
| 4 |
| 1 |
| 2 |
点评:本题考查了分式的化简求值.分式的混合运算需特别注意运算顺序及符号的处理,也需要对通分、分解因式、约分等知识点熟练掌握.
练习册系列答案
相关题目