题目内容
先化简,再求值(| x-1 |
| x+1 |
| x+1 |
| x+2 |
| x+3 |
| x2-4 |
| 2 |
分析:先通分,然后进行四则运算,最后将x=
-1代入.
| 2 |
解答:解:原式=
÷
=
•
=
•
=-
(4分)
把x=
-1代入上式得:
原式=-
=-
=
-1.(5分)
| (x-1)(x+2)-(x+1)2 |
| (x+1)(x+2) |
| x+3 |
| (x+2)(x-2) |
=
| x2+x-2-(x2+2x+1) |
| (x+1)(x+2) |
| (x+2)(x-2) |
| x+3 |
=
| -(x+3) |
| (x+1)(x+2) |
| (x+2)(x-2) |
| x+3 |
=-
| x-2 |
| x+1 |
把x=
| 2 |
原式=-
| ||
|
| ||
|
| 3 |
| 2 |
| 2 |
点评:本题考查了分式的化简求值,解答此题的关键是把分式化到最简,然后代值计算.
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