题目内容
计算:
(1)
•
;
(2)
+
.
(1)
| a2 |
| a+3 |
| a2-9 |
| 6a |
(2)
| 2m |
| m2-4 |
| m |
| m+2 |
(1)原式=
•
=
;
(2)原式=
+
=
=
.
| a2 |
| a+3 |
| (a+3)(a-3) |
| 6a |
=
| a(a-3) |
| 6 |
(2)原式=
| 2m |
| (m+2)(m-2) |
| m(m-2) |
| (m+2)(m-2) |
=
| 2m+m2-2m |
| (m+2)(m-2) |
=
| m2 |
| m2-4 |
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