题目内容
83
83
°.分析:根据角平分线定义得出∠DOC=
∠AOC,∠EOC=
∠BOC,求出∠DOE=
∠AOB,代入求出即可.
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解答:解:∵OD是∠AOC的平分线,OE是∠BOC的平分线,
∴∠DOC=
∠AOC,∠EOC=
∠BOC,
∴∠DOE=∠DOC+∠EOC
=
∠AOC+
∠BOC
=
(∠AOC+∠BOC)
=
∠AOB
=
×166°
=83°.
故答案为:83.
∴∠DOC=
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∴∠DOE=∠DOC+∠EOC
=
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=
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=
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=
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=83°.
故答案为:83.
点评:本题考查了角平分线定义和角的有关计算的应用,关键是推出∠DOE=
∠AOB.
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