题目内容
| 1 |
| x-10 |
| 1 |
| x-6 |
| 1 |
| x-7 |
| 1 |
| x-9 |
分析:直接去分母,计算比较麻烦,也易造成计算的错误,因此应先移项,再对方程两边分别通分求解.
解答:解:移项得
-
=
-
,
两边同时通分得,
=
,
即
=
,
∴(x-10)(x-9)=(x-7)(x-6),
∴x=8,
检验,当x=8时,(x-10)(x-9)(x-7)(x-6)≠0,所以x=8是原方程的根.
| 1 |
| x-10 |
| 1 |
| x-9 |
| 1 |
| x-7 |
| 1 |
| x-6 |
两边同时通分得,
| x-9-(x-10) |
| (x-10)(x-9) |
| x-6-(x-7) |
| (x-7)(x-6) |
即
| 1 |
| (x-10)(x-9) |
| 1 |
| (x-7)(x-6) |
∴(x-10)(x-9)=(x-7)(x-6),
∴x=8,
检验,当x=8时,(x-10)(x-9)(x-7)(x-6)≠0,所以x=8是原方程的根.
点评:如果要求的分式方程比较复杂时,不要进入解方程的程序,一般的,可以通过分式的运算性质进行化简后,再去分母进行解答.
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