题目内容
[(a-2)-3]-1=______.x2y(x-3y)-1=______.(
)-4=______.
| xy |
| 2x2 |
[(a-2)-3]-1=(a6)-1=a-6=
;
x2y(x-3y)-1=x2y(x3y-1)=x6;
(
)-4=
=
.
| 1 |
| a6 |
x2y(x-3y)-1=x2y(x3y-1)=x6;
(
| xy |
| 2x2 |
| 1 | ||
(
|
| 16x4 |
| y4 |
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