题目内容
先化简,再求值:
÷[(x+2)-
],其中x=1.
| x-3 |
| x-2 |
| 5 |
| x-2 |
原式=
÷
=
•
=
,
当x=1时,原式=
.
| x-3 |
| x-2 |
| x2-9 |
| x-2 |
=
| x-3 |
| x-2 |
| x-2 |
| (x+3)(x-3) |
=
| 1 |
| x+3 |
当x=1时,原式=
| 1 |
| 4 |
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题目内容
| x-3 |
| x-2 |
| 5 |
| x-2 |
| x-3 |
| x-2 |
| x2-9 |
| x-2 |
| x-3 |
| x-2 |
| x-2 |
| (x+3)(x-3) |
| 1 |
| x+3 |
| 1 |
| 4 |