题目内容
已知x=1+| 3 |
| 1 |
| x+2 |
| 1 |
| x2-4 |
| 1 |
| x-2 |
分析:题目算式比较多,经观察分母中含有公因式(x+2)(x-2),所以先通分化简后再代入求解.
解答:解:
+
-
=
+
=
=
=-
.
故答案为-
.
| 1 |
| x+2 |
| 1 |
| x2-4 |
| 1 |
| x-2 |
| -4 |
| x2-4 |
| 1 |
| x2-4 |
| -3 |
| x2-4 |
| -3 | ||
(1+
|
| ||
| 2 |
故答案为-
| ||
| 2 |
点评:异分母分式相加减,先通分再加减,注意结果要化简,再代入值计算.
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