ÌâÄ¿ÄÚÈÝ

ÔĶÁÏÂÁжÌÎÄ£¬²¢»Ø´ðÌâºóÎÊÌ⣺

һλũ·òÁÙÖÕǰ°ÑËûµÄËĸö¶ù×ӽе½´²Ç°Ëµ£º¡°ÎÒûʲôÁô¸øÄãÃǵģ¬Ö»ÓÐ׿ÉÏÁôϵļ¸Ê®Ä¶µØ£®ÎÒËÀºó£¬ÄãÃǰÑËü·ÖÁ˰ɣ¬ÎªÁ˱ÜÃâÕù³³£¬ÄãÃÇ»¹ÊÇÆ½·Ö°É£®¡±Å©·òËÀºó£¬ËûµÄËĸö¶ù×Ó¿ªÊ¼·ÖµØ£¬ÈçͼËùʾ£¬µØÀïÇ¡ºÃÓÐËĿھ®£¬ËÄ¿ÃÊ÷£¬ËûÃǾö¶¨·Ö³ÉÃæ»ý¡¢ÐÎ×´ÏàͬµÄËĿ飬²¢ÇÒÿÈËÒ»¿Ú¾®£¬Ò»¿ÃÊ÷£¬µ«ËûÃÇ×ó±È±È£¬ÓÒ»­»­£¬²»ÖªÔõô·Ö£®

ͬѧÃÇ£¬ÇëÏëÏëÔõÑù²ÅÄܰ´ÒªÇó°ÑµØ·Ö¿ªÄØ£¿

´ð°¸£º
½âÎö£º

¡¡¡¡´ð°¸£ºÀýÈ磺ͼÖÐÓÃÁË4¸ö²»Í¬ÑÕÉ«Çø±ð£®

¡¡¡¡½âÎö£º¹Û²ìͼÐεÄÌØÕ÷£¬¾®ÓëÊ÷µÄλÖÃÔÚÓÒÉÏ¡¢×óϵķֲ¼Ïàͬ£¬Ãæ»ý¿ÉÒÔ¿´×÷ÊÇ24¸öµ¥Î»£¬Ã¿ÈËÓ¦·ÖµÃ6¸ö£¬ÔÚ³¤·½ÐεÄÒ»Ìõ¶Ô½ÇÏßµÄ×óϲ¿·Ö·Ö³öÁ½¸öº¬6¸öÃæ»ýµÄͼÐΣ¬ÓÒÉÏÏàͬ£®


Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
¾«Ó¢¼Ò½ÌÍøÏÈÔĶÁ¶ÌÎÄ£¬Ôٻشð¶ÌÎĺóÃæµÄÎÊÌ⣮
Æ½ÃæÄÚÓëÒ»¸ö¶¨µãFºÍÒ»Ìõ¶¨Ö±ÏßlµÄ¾àÀëÏàµÈµÄµãµÄ¹ì¼£½Ð×öÅ×ÎïÏߣ¬µãF½Ð×öÅ×ÎïÏߵĽ¹µã£¬Ö±Ïßl½Ð×öÅ×ÎïÏßµÄ×¼Ïߣ®
ÏÂÃæ¸ù¾ÝÅ×ÎïÏߵ͍Ò壬ÎÒÃÇÀ´ÇóÅ×ÎïÏߵķ½³Ì£®
ÈçÉÏͼ£¬½¨Á¢Ö±½Ç×ø±êϵxoy£¬Ê¹xÖá¾­¹ýµãFÇÒ´¹Ö±ÓÚÖ±Ïßl£¬´¹×ãΪK£¬²¢Ê¹Ô­µãÓëÏß¶ÎKFµÄÖеãÖØºÏ£®Éè|KF|=p£¨p£¾0£©£¬ÄÇô½¹µãFµÄ×ø±êΪ£¨
p
2
£¬0£©£¬×¼ÏßlµÄ·½³ÌΪx=-
p
2
£®
ÉèµãM£¨x£¬y£©ÊÇÅ×ÎïÏßÉÏÈÎÒâÒ»µã£¬µãMµ½lµÄ¾àÀëΪd£¬ÓÉÅ×ÎïÏߵ͍Ò壬Å×ÎïÏß¾ÍÊÇÂú×ã|MF|=dµÄµãMµÄ¹ì¼££®
¡ß|MF|=
(x-
p
2
)
2
+y2
£¬d=|x+
p
2
|¡à
(x-
p
2
)
2
+y2
=|x+
p
2
|
½«ÉÏʽÁ½±ßƽ·½²¢»¯¼ò£¬µÃy2=2px£¨p£¾0£©¢Ù
·½³Ì¢Ù½Ð×öÅ×ÎïÏߵıê×¼·½³Ì£¬Ëü±íʾµÄÅ×ÎïÏߵĽ¹µãÔÚxÖáµÄÕý°ëÖáÉÏ£¬×ø±êÊÇ£¨
p
2
£¬0£©£¬ËüµÄ×¼Ïß·½³ÌÊÇx=-
p
2
£®
Ò»ÌõÅ×ÎïÏߣ¬ÓÉÓÚËüÔÚ×ø±êÆ½ÃæÄÚµÄλÖò»Í¬£¬·½³ÌÒ²²»Í¬£®ËùÒÔÅ×ÎïÏߵıê×¼·½³Ì»¹ÓÐÆäËüµÄ¼¸ÖÖÐÎʽ£ºy2=-2px£¬x2=2py£¬x2=-2py£®ÕâËÄÖÖÅ×ÎïÏߵıê×¼·½³Ì£¬½¹µã×ø±êÒÔ¼°×¼Ïß·½³ÌÁбíÈçÏ£º
±ê×¼·½³Ì  ½»µã×ø±ê  ×¼Ïß·½³Ì 
 y2=2px£¨p£¾0£©  £¨
p
2
£¬0
£©
 x=-
p
2
 y2=-2px£¨p£¾0£©  £¨-
p
2
£¬0
£©
 x=
p
2
 x2=2py£¨p£¾0£©  £¨0£¬
p
2
£©
 y=-
p
2
 x2=-2py£¨p£¾0£©  £¨0£¬-
p
2
£©
 y=-
p
2
½â´ðÏÂÁÐÎÊÌ⣺
£¨1£©¢ÙÒÑÖªÅ×ÎïÏߵıê×¼·½³ÌÊÇy2=8x£¬ÔòËüµÄ½¹µã×ø±êÊÇ
 
£¬×¼Ïß·½³ÌÊÇ
 

¢ÚÒÑÖªÅ×ÎïÏߵĽ¹µã×ø±êÊÇF£¨0£¬-6£©£¬ÔòËüµÄ±ê×¼·½³ÌÊÇ
 
£®
£¨2£©µãMÓëµãF£¨4£¬0£©µÄ¾àÀë±ÈËüµ½Ö±Ïßl£ºx+5=0µÄ¾àÀëС1£¬ÇóµãMµÄ¹ì¼£·½³Ì£®
£¨3£©Ö±Ïßy=
3
x+b
¾­¹ýÅ×ÎïÏßy2=4xµÄ½¹µã£¬ÓëÅ×ÎïÏßÏཻÓÚÁ½µãA¡¢B£¬ÇóÏß¶ÎABµÄ³¤£®

ÏÈÔĶÁ¶ÌÎÄ£¬Ôٻشð¶ÌÎĺóÃæµÄÎÊÌ⣮
Æ½ÃæÄÚÓëÒ»¸ö¶¨µãFºÍÒ»Ìõ¶¨Ö±ÏßlµÄ¾àÀëÏàµÈµÄµãµÄ¹ì¼£½Ð×öÅ×ÎïÏߣ¬µãF½Ð×öÅ×ÎïÏߵĽ¹µã£¬Ö±Ïßl½Ð×öÅ×ÎïÏßµÄ×¼Ïߣ®
ÏÂÃæ¸ù¾ÝÅ×ÎïÏߵ͍Ò壬ÎÒÃÇÀ´ÇóÅ×ÎïÏߵķ½³Ì£®
ÈçÉÏͼ£¬½¨Á¢Ö±½Ç×ø±êϵxoy£¬Ê¹xÖá¾­¹ýµãFÇÒ´¹Ö±ÓÚÖ±Ïßl£¬´¹×ãΪK£¬²¢Ê¹Ô­µãÓëÏß¶ÎKFµÄÖеãÖØºÏ£®Éè|KF|=p£¨p£¾0£©£¬ÄÇô½¹µãFµÄ×ø±êΪ£¨Êýѧ¹«Ê½£¬0£©£¬×¼ÏßlµÄ·½³ÌΪx=-Êýѧ¹«Ê½£®
ÉèµãM£¨x£¬y£©ÊÇÅ×ÎïÏßÉÏÈÎÒâÒ»µã£¬µãMµ½lµÄ¾àÀëΪd£¬ÓÉÅ×ÎïÏߵ͍Ò壬Å×ÎïÏß¾ÍÊÇÂú×ã|MF|=dµÄµãMµÄ¹ì¼££®
¡ß|MF|=Êýѧ¹«Ê½£¬d=|x+Êýѧ¹«Ê½|¡àÊýѧ¹«Ê½=|x+Êýѧ¹«Ê½|
½«ÉÏʽÁ½±ßƽ·½²¢»¯¼ò£¬µÃy2=2px£¨p£¾0£©¢Ù
·½³Ì¢Ù½Ð×öÅ×ÎïÏߵıê×¼·½³Ì£¬Ëü±íʾµÄÅ×ÎïÏߵĽ¹µãÔÚxÖáµÄÕý°ëÖáÉÏ£¬×ø±êÊÇ£¨Êýѧ¹«Ê½£¬0£©£¬ËüµÄ×¼Ïß·½³ÌÊÇx=-Êýѧ¹«Ê½£®
Ò»ÌõÅ×ÎïÏߣ¬ÓÉÓÚËüÔÚ×ø±êÆ½ÃæÄÚµÄλÖò»Í¬£¬·½³ÌÒ²²»Í¬£®ËùÒÔÅ×ÎïÏߵıê×¼·½³Ì»¹ÓÐÆäËüµÄ¼¸ÖÖÐÎʽ£ºy2=-2px£¬x2=2py£¬x2=-2py£®ÕâËÄÖÖÅ×ÎïÏߵıê×¼·½³Ì£¬½¹µã×ø±êÒÔ¼°×¼Ïß·½³ÌÁбíÈçÏ£º
±ê×¼·½³Ì ½»µã×ø±ê ×¼Ïß·½³Ì
y2=2px£¨p£¾0£© £¨Êýѧ¹«Ê½£© x=-Êýѧ¹«Ê½
y2=-2px£¨p£¾0£© £¨-Êýѧ¹«Ê½£© x=Êýѧ¹«Ê½
x2=2py£¨p£¾0£© £¨0£¬Êýѧ¹«Ê½£© y=-Êýѧ¹«Ê½
x2=-2py£¨p£¾0£© £¨0£¬-Êýѧ¹«Ê½£© y=-Êýѧ¹«Ê½
½â´ðÏÂÁÐÎÊÌ⣺
£¨1£©¢ÙÒÑÖªÅ×ÎïÏߵıê×¼·½³ÌÊÇy2=8x£¬ÔòËüµÄ½¹µã×ø±êÊÇ______£¬×¼Ïß·½³ÌÊÇ______
¢ÚÒÑÖªÅ×ÎïÏߵĽ¹µã×ø±êÊÇF£¨0£¬-6£©£¬ÔòËüµÄ±ê×¼·½³ÌÊÇ______£®
£¨2£©µãMÓëµãF£¨4£¬0£©µÄ¾àÀë±ÈËüµ½Ö±Ïßl£ºx+5=0µÄ¾àÀëС1£¬ÇóµãMµÄ¹ì¼£·½³Ì£®
£¨3£©Ö±ÏßÊýѧ¹«Ê½¾­¹ýÅ×ÎïÏßy2=4xµÄ½¹µã£¬ÓëÅ×ÎïÏßÏཻÓÚÁ½µãA¡¢B£¬ÇóÏß¶ÎABµÄ³¤£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø