题目内容
计算:(1)
| 12 |
| 48 |
| 32 |
(2)
| 45 |
|
2
|
(3)
| 3a2 |
|
| 1 |
| 2 |
|
(4)(
| 3 |
| 2 |
| 6 |
分析:(1)利用二次根式的运算性质,加减运算首先进行化简开平方,使二次根式达到最简,再进行合并被开方数相同的二次根式;
(2)利用二次根式的运算性质,除法首先变成乘法运算,根号内的与根号内的相乘,根号外的与根号外的相乘;
(3)利用以上性质进行运算;
(4)利用以上性质进行运算;
(2)利用二次根式的运算性质,除法首先变成乘法运算,根号内的与根号内的相乘,根号外的与根号外的相乘;
(3)利用以上性质进行运算;
(4)利用以上性质进行运算;
解答:解:(1)
-
+
=2
-4
+4
,
=(2-4)
+4
,
=-2
+4
;
(2)
÷
×
=
×
×
,
=
,
=10
;
(3)
÷3
×
=
×
×
,
=
×
×
,
=
×2a,
=
;
(4)(
-
)2×(5+2
)
=(3+2-2
)×(5+2
),
=(5-2
)×(5+2
),
=25-24,
=1.
| 12 |
| 48 |
| 32 |
=2
| 3 |
| 3 |
| 2 |
=(2-4)
| 3 |
| 2 |
=-2
| 3 |
| 2 |
(2)
| 45 |
|
2
|
=
| 45 |
| 5 |
2
|
=
45×5×
|
=10
| 6 |
(3)
| 3a2 |
|
| 1 |
| 2 |
|
=
| 3a 2 |
| 1 |
| 3 |
|
| 1 |
| 2 |
|
=
| 1 |
| 3 |
| 1 |
| 2 |
3a 2×
|
=
| 1 |
| 6 |
=
| a |
| 3 |
(4)(
| 3 |
| 2 |
| 6 |
=(3+2-2
| 6 |
| 6 |
=(5-2
| 6 |
| 6 |
=25-24,
=1.
点评:此题主要考查了二次根式的混合运算,在运算二次根式的乘除运算时,根号内的与根号内的相乘,根号外的与根号外的相乘;
是解决问题的关键.
是解决问题的关键.
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