题目内容
已知x=
,则x3+2x2-5= .
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考点:二次根式的化简求值
专题:
分析:先化简x=
=
,再把x3+2x2-5=x(x+1)2-x-5,进一步代入求得数值即可.
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|
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解答:解:∵x=
=
,
∴x3+2x2-5
=x(x+1)2-x-5
=
×(
+1)2-
-5
=
×
×
-
-5
=
+1-
-5
=
.
故答案为:
.
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|
| ||
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∴x3+2x2-5
=x(x+1)2-x-5
=
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=
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| 2 |
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=
| 5 |
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=
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故答案为:
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点评:此题考查二次根式的混合运算,注意巧妙利用公式法因式分解,先化简,再求值.
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