题目内容

计算:
(1)(2x+1)(-2x+1)
(2)(2a-
1
2
b22
(3)(3x+1)2(3x-1)2
(4)(x+1)(x2+1)(x4+1)(x-1)
(1)(2x+1)(-2x+1),
=12-(2x)2
=1-4x2

(2)(2a-
1
2
b22
=(2a)2-2×2a×
1
2
b2+(
1
2
b2)
2

=4a2-2ab2+
1
4
b4


(3)(3x+1)2(3x-1)2
=[(3x+1)(3x-1)]2
=(9x2-1)2
=81x4-18x2+1;

(4)(x+1)(x2+1)(x4+1)(x-1),
=(x+1)(x-1)(x2+1)(x4+1),
=(x2-1)(x2+1)(x4+1),
=(x4-1)(x4+1),
=x8-1.
练习册系列答案
相关题目

违法和不良信息举报电话:027-86699610 举报邮箱:58377363@163.com

精英家教网