题目内容
化简：(a-| a |
| a+1 |
| a2-2a |
| a2-4 |
| 1 |
| a+2 |
分析：首先把括号里的式子进行通分，然后把除法运算转化成乘法运算，最后进行约分化简．
解答：解：(a-
)÷
×
=(a-
)×
×
=(a-
)×
=a×
-
×
=1-
=
．
| a |
| a+1 |
| a2-2a |
| a2-4 |
| 1 |
| a+2 |
=(a-
| a |
| a+1 |
| (a+2)(a-2) |
| a(a-2) |
| 1 |
| a+2 |
=(a-
| a |
| a+1 |
| 1 |
| a |
=a×
| 1 |
| a |
| a |
| a+1 |
| 1 |
| a |
=1-
| 1 |
| a+1 |
=
| a |
| a+1 |
点评：分式的四则运算是整式四则运算的进一步发展，在计算时，首先要弄清楚运算顺序，先去括号，再进行分式的乘除．
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