题目内容
计算:(1)3
|
| (-3)2 |
| 3 |
| 12 |
(2)先化简,再求值:x+1-
| x2 |
| x-1 |
| 2 |
分析:(1)先将二次根式化为最简,然后合并同类二次根式即可得出答案;
(2)将x+1看作整体与分式进行通分,然后可得出最简的式子,进而将x的值代入即可得出答案.
(2)将x+1看作整体与分式进行通分,然后可得出最简的式子,进而将x的值代入即可得出答案.
解答:解:(1)3
+
-(1-
)-
,
=
+3-1+
-2
,
=2;
(2)x+1-
,
=
,
=
,
当x=
-1时,原式=
=-
=2+
.
|
| (-3)2 |
| 3 |
| 12 |
=
| 3 |
| 3 |
| 3 |
=2;
(2)x+1-
| x2 |
| x-1 |
=
| x2- 1-x2 |
| x-1 |
=
| -1 |
| x-1 |
当x=
| 2 |
| -1 |
| x-1 |
| 1 | ||
|
| 2 |
点评:本题考查二次根式的加减法及分式的化简求值,属于基础性题目,难度不大,在解答此类题目是要注意先将二次根式化为最简,然后合并同类二次根式.
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