题目内容
计算：| 2x-6 |
| x-2 |
| 5 |
| x-2 |
分析：首先把括号里的分式进行通分，然后进行约分化简．
解答：解：原式=
÷[
-(x+2)]
=
÷[
-
]
=
÷
=
÷
=
•
=2(x-3)•
=-
．
| 2x-6 |
| x-2 |
| 5 |
| x-2 |
=
| 2(x-3) |
| x-2 |
| 5 |
| x-2 |
| (x+2)(x-2) |
| x-2 |
=
| 2(x-3) |
| x-2 |
| 5-(x2-4) |
| x-2 |
=
| 2(x-3) |
| x-2 |
| 9-x2 |
| x-2 |
=
| 2(x-3) |
| x-2 |
| x-2 |
| (3+x)(3-x) |
=2(x-3)•
| 1 |
| -(x+3)(x-3) |
| 2 |
| x+3 |
点评：分式的四则运算是整式四则运算的进一步发展，在计算时，首先要弄清楚运算顺序，先去括号，再进行分式的乘除．
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