题目内容
先化简,再求值:| 3x-3 |
| x2-1 |
| 3x |
| x+1 |
| 1 |
| x-1 |
分析:先算除法,再算减法,最后将x=2代入.
解答:解:
÷
-
=
•
-
=
-
=
-
=-
,
当x=2时,原式=-
.
| 3x-3 |
| x2-1 |
| 3x |
| x+1 |
| 1 |
| x-1 |
=
| 3(x-1) |
| (x+1)(x-1) |
| x+1 |
| 3x |
| 1 |
| x-1 |
=
| 1 |
| x |
| 1 |
| x-1 |
=
| x-1 |
| x(x-1) |
| x |
| x(x-1) |
=-
| 1 |
| x(x-1) |
当x=2时,原式=-
| 1 |
| 2 |
点评:本题考查了分式的化简求值.解答此题的关键是把分式化到最简,然后代值计算.
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