题目内容
化简下列各式:(1)
| 2a |
| a2-4 |
| 1 |
| 2-a |
(2)(-
| a2 |
| b |
| b2 |
| a |
| b |
| a |
(3)
| 3-x |
| 2x-4 |
| 5 |
| x-2 |
(4)(
| x |
| x-y |
| 2y |
| x-y |
| xy |
| x-2y |
| 1 |
| x |
| 1 |
| y |
分析:对于一般的分式混合运算来讲,其运算顺序与整式混合运算一样,是先乘方,再乘除,最后算加减,如果遇括号要先算括号里面的.在此基础上,有时也应该根据具体问题的特点,灵活应变,注意方法.
解答:解:(1)原式=
=
;
(2)原式=a2b3;
(3)原式=
÷
=
×
=-
;
(4)原式=
×
×
=
.
故答案为
、a2b3、-
、
.
| 2a-a-2 |
| (a+2)(a-2) |
=
| 1 |
| a+2 |
(2)原式=a2b3;
(3)原式=
| 3-x |
| 2(x-2) |
| x2-9 |
| x-2 |
=
| 3-x |
| 2(x-2) |
| x-2 |
| (x+3)(x-3) |
=-
| 1 |
| 2(x+3) |
(4)原式=
| x-2y |
| x-y |
| xy |
| x-2y |
| xy |
| x+y |
=
| x2y2 |
| x2-y2 |
故答案为
| 1 |
| a+2 |
| 1 |
| 2(x+3) |
| x2y2 |
| x2-y2 |
点评:有理数的混合运算首先要弄清楚运算顺序,先去括号,再进行有理数的乘除,最后是加减.
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