题目内容
| 1 |
| 3 |
| AC |
| b |
| BA |
| c |
| b |
| c |
| DE |
| 1 |
| 3 |
| b |
| 1 |
| 3 |
| c |
| 1 |
| 3 |
| b |
| 1 |
| 3 |
| c |
分析:在Rt△ABC中,DE∥BC,AD=
AB,则
=
,又
=
+
=
+
,继而即可求出答案.
| 1 |
| 3 |
| DE |
| 1 |
| 3 |
| BC |
| BC |
| BA |
| AC |
| c |
| b |
解答:解:∵DE∥BC,AD=
AB,
∴
=
,
又
=
+
=
+
,
∴
=
(
+
)=
+
.
故答案为:
+
.
| 1 |
| 3 |
∴
| DE |
| 1 |
| 3 |
| BC |
又
| BC |
| BA |
| AC |
| c |
| b |
∴
| DE |
| 1 |
| 3 |
| b |
| c |
| 1 |
| 3 |
| b |
| 1 |
| 3 |
| c |
故答案为:
| 1 |
| 3 |
| b |
| 1 |
| 3 |
| c |
点评:本题考查平面向量的知识,难度适中,解题关键是掌握平面向量的加法法则.
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