题目内容
计算:(1)
| 27 |
| 1 |
| 2 |
| 3 |
(2)
| 2 |
| a2-1 |
| 1 |
| a+1 |
分析:(1)分别根据二次根式的化简、特殊角的三角函数值、负整数指数幂及绝对值的性质计算出各数,再根据实数混合运算的法则进行计算即可;
(2)先通分,再分母不变,分子相加即可.
(2)先通分,再分母不变,分子相加即可.
解答:解:(1)
-2cos30°+(
)-2-|1-
|,
=3
-2×
+4-
+1,
=3
-
+5-
,
=
+5;
(2)
+
,
=
+
,
=
,
=
,
=
.
故答案为:
+5,
.
| 27 |
| 1 |
| 2 |
| 3 |
=3
| 3 |
| ||
| 2 |
| 3 |
=3
| 3 |
| 3 |
| 3 |
=
| 3 |
(2)
| 2 |
| a2-1 |
| 1 |
| a+1 |
=
| 2 |
| a2-1 |
| a-1 |
| a2-1 |
=
| 2+a-1 |
| a2-1 |
=
| a+1 |
| a2-1 |
=
| 1 |
| a-1 |
故答案为:
| 3 |
| 1 |
| a-1 |
点评:本题考查的是二次根式的化简、特殊角的三角函数值、负整数指数幂、绝对值的性质及分式的加减法,在解答(2)时一定要注意把最后结果化为最简形式.
练习册系列答案
相关题目